Calculate the number of degrees of freedom of molecules of hydrogen in 1 cc of hydrogen gas at NTP.

Answer

`1.344 xx 10^(20)`

Explanation

Volume occupied by 1 gram mole of every gas at NTP = 22400 c.c.
`:.` No of molecules in 1 c.c of hydrogen
`=(6.023 xx 10^(23))/(22400) = 2.688 xx 10^(19)`
As each molecules has 5 degree of freedom (hydrogen being diatomic)
`= 5 xx 2.688 xx 10^(19) = 1.344 xx 10^(20)`