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Estimate the temperature at which the ox...

Estimate the temperature at which the oxygen molecules will have the same rms velocity as hydrogen molecules at `150^(@)C`. Molecular weight of oxygen is 32 and that of hydrogen is 2.

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To solve the problem, we need to find the temperature at which the root mean square (rms) velocity of oxygen molecules equals the rms velocity of hydrogen molecules at 150°C. ### Step-by-Step Solution: 1. **Convert the Temperature of Hydrogen to Kelvin:** The temperature of hydrogen is given as 150°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] Thus, \[ T_{H2} = 150 + 273 = 423 \, K \] **Hint:** Remember that to convert Celsius to Kelvin, you always add 273. 2. **Write the Formula for rms Velocity:** The root mean square velocity (Vrms) is given by the formula: \[ V_{rms} = \sqrt{\frac{3RT}{M}} \] where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( M \) is the molecular weight in kg/mol. 3. **Set the rms Velocities Equal:** Since we want the rms velocity of oxygen (\( V_{rms(O2)} \)) to equal that of hydrogen (\( V_{rms(H2)} \)), we can set up the equation: \[ \sqrt{\frac{3R T_{O2}}{M_{O2}}} = \sqrt{\frac{3R T_{H2}}{M_{H2}}} \] Here, \( M_{O2} = 32 \, g/mol = 0.032 \, kg/mol \) and \( M_{H2} = 2 \, g/mol = 0.002 \, kg/mol \). 4. **Square Both Sides:** Squaring both sides to eliminate the square root gives: \[ \frac{3R T_{O2}}{M_{O2}} = \frac{3R T_{H2}}{M_{H2}} \] The \( 3R \) cancels out: \[ \frac{T_{O2}}{M_{O2}} = \frac{T_{H2}}{M_{H2}} \] 5. **Rearrange to Solve for \( T_{O2} \):** Rearranging the equation gives: \[ T_{O2} = T_{H2} \cdot \frac{M_{O2}}{M_{H2}} \] 6. **Substitute the Known Values:** Substitute \( T_{H2} = 423 \, K \), \( M_{O2} = 32 \, g/mol \), and \( M_{H2} = 2 \, g/mol \): \[ T_{O2} = 423 \cdot \frac{32}{2} \] \[ T_{O2} = 423 \cdot 16 = 6768 \, K \] 7. **Convert the Temperature Back to Celsius:** To convert \( T_{O2} \) back to Celsius: \[ T_{O2}(°C) = T_{O2}(K) - 273 \] \[ T_{O2}(°C) = 6768 - 273 = 6495 \, °C \] ### Final Answer: The estimated temperature at which the oxygen molecules will have the same rms velocity as hydrogen molecules at 150°C is **6495°C**.

To solve the problem, we need to find the temperature at which the root mean square (rms) velocity of oxygen molecules equals the rms velocity of hydrogen molecules at 150°C. ### Step-by-Step Solution: 1. **Convert the Temperature of Hydrogen to Kelvin:** The temperature of hydrogen is given as 150°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 ...
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