Calculate the temperature at which the rms velocity of hydrogen will be equal to `8 km//s. Take R = 8.31 J "mole"^(-1) K^(-1)`

Answer

`5134.4 K`

Explanation

Here, `T = ? C_(rms) = 8 km//s = 8 xx 10^(3) m//s`.
`R= 8.31 "mole"^(-1)K^(-1)`
Molecular weight of hydrogen
`M= 2 g = 2 xx 10^(-3) kg`
From `C_(rms) = sqrt((3RT)/(M)) T = (C_(rms)^(2) xx M)/(3R)`
`=((8xx10^(3))^(2) xx 2 xx 10^(-3))/(3xx 8.31)`
`T = 5134.4 K`