A gaseous mixture consists of 16 g of helium and 16 g of oxygen. Find `gamma` for the mixture.

Answer

`1.62`

Explanation

Number of moles , `n_(1) = 16/4 = 4 , n_(2) = 16/32 = 1/2`
`He , C_(upsilon) = 3/2 R`, For oxygen , `C_(upsilon) = 5/2 R`
`C_(upsilon)(mixture) = (4 xx 3/2 R + 1/2 xx 5/2 R)/(4 +1/2) = 29/18 R`
`gamma(mix) = 1+(R)/(C_(upsilon)(mic)) = 1+ r/(29//18 R)`
`=1+18/29 = 47/29 = 1.62`