Calculate the total number of degree of freedom possessed by 10 c.c. of hydrogen gas at N.T.P

Answer

`1.34375 xx 10^(21)`

Explanation

Number of hydrogen molecules in `22400` c.c.
`= 6.02 xx 10^(23) at NTP`
`:.` Number of hydrogen molecules in `10 c.c.`
`=(6.02 xx 10^(23) xx 10)/(22400)` at NTP
As hydrogen is diatomic gas, each molecule has 5 degree of freedom.
`:.` Total no. of degree of freedom
`= (5 xx 6.02 xx 10^(23) xx10)/(22400) = 1.34375 xx 10^(21)`