The specific heat of the mixture of two gases at constant volume is `(13)/(6) R`. The ratio of the number of moles of the first gas to the second gas is 1:2.
The respective gases may be

Options

A. `O_(2), H_(2)`
B. He, Ne
C. `N_(2), He`
D. `He, N_(2)`

Answer

D

Explanation

As `C_(upsilon) = (n_(1)(C_(upsilon_1))+n_(2)(C_(upsilon_2)))/(n_(1)+n_(2)) = 13/6 R`
`:. (1(C_(upsilon_1))+2(C_(upsilon_2)))/(1+2) = 13/6 R`
`:. C_(upsilon_1)+2C_(upsilon_2) = 13/2 R`
If !st gas is monoatomic , `C_(upsilon_1) = 3/2 R`, and
2nd gas is diatomic, `C_(upsilon_2)=5/2 R`, then
`C_(upsilon_1)+2C_(upsilon_2) = 3/2 R + 5R = 13/2 R`. Hence , choice (d) is correct.