A certain amount of gas is sealed in a glass flask at 1 atmosphere pressure and `20^(@)C`. The flask can withstand upto a pressure of 2 atmosphere. Find the temperature to which gas can be heated so that the flask does not break.

Options

A. `513^(@)C`
B. `413^(@)C`
C. `313^(@)C`
D. `213^(@)C`

Answer

C

Explanation

Here, `P_(1) = 1 atm, P_(2) = 2 atm, T_(1) = 20^(@)C, T_(2)=?`
As volume remains constant
`:. (P_1)/(T_1) = (P_2)/(T_2)`
`:. T_(2) = T_(1)(P_2)/(P_1) = (20+273) xx 2/1 = 293 xx 2 = 586K`
`= 586 - 273 = 313^(@)C`.