One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm are introduced into a vessel of volume 1 litre. If there is no change in temperature, the final pressure of the mixture of gas (in atm) is

Options

A. 1.5
B. 2.5
C. 2
D. 4

Answer

C

Explanation

For oxygen , `P_(1)V_(1) = P_(2)V_(2)`
or, ` 1 xx 1 = P_(2) xx 1 or P_(2) = 1 atm` ..(i)
For nitrogen , `P_(1)^(') V_(1)^(') = P_(2)^(')V_(2)^(')`
or `0.5xx 2 = P_(2)^(') xx 1`
or `P_(2)^(') = 1 atm`
`:. P = P_(2) +P_(2)^(') = 1 + 1 = 2 atm`.