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Consider an ideal gas confined in an iso...

Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increase as `V^q`, where V is the volume of the gas. The value of q is : `(gamma=(C_p)/(C_v))`

A

`(3(gamma) + 5)/6`

B

`(3(gamma) - 5)/6`

C

`((gamma) + 1)/2`

D

`((gamma) - 5)/2`

Text Solution

Verified by Experts

The correct Answer is:
C

Average time of collision, `tau = (lambda)/(upsilon_(rms))`
as, `lambda = (1)/(sqrt(2)pi d^(2)(N/V)) and upsilon_(rms) = sqrt((3RT)/(m))`
`:.tau = (1)/(sqrt(2)pi d^(2)(N/V) sqrt((3RT)/(m))) :. Tau prop (V)/(sqrt(T))`
In adiabatic expansion `TV^(gamma-1) = k or T prop V^(1-gamma)`
As `tau prop (V)/(sqrt(T)) prop (V)/(sqrt(V^(1-gamma))) or tau prop V (V^(1-gamma))^(-1/2)`
or, `tau = V^((1_gamma)/(2))`. On comparing with `V^(q)`, we get
`q = (1+gamma)/(2) prop (gamma +1)/(2)`.
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