The mean free path of molecules of a gas (radius r) is inversely proportional to

Options

A. `r^(3)`
B. `r^(2)`
C. r
D. `sqrt(r)`

Answer

B

Explanation

Mean free path `(lambda)` of the molecules of a gas is given by
` lambda = (1)/(pid^(2)nsqrt(2)) = (1)/(pi (2r)^(2)nsqrt(2)) = (1)/(4sqrt(2)pi r^(2)n)`
therefore, `lambda prop 1//r^(2)`.