The pressure exerted by an ideal gas is `P = (1)/(3) (M)/(V)C^(2)`, where the symbols have their usual meaning. Using standard gas equation, PV = RT, we find that `C^(2) = (3 RT)/(M) or C^(2) oo T`. Average kinetic energy of translation of one mole of gas ` =(1)/(2) MC^(2) = (3 RT)/(2)` with the help of the passage given above, choose the most appropriate alternative for each of the following quetions :
Average thermal energy of one mole of helium at this temperature is (Given gas constant for 1 gram mole `=8.31 J "mole"^(-1) K^(-1)`.

Options

A. `3.74 xx 10^(3) J`
B. `3.74 xx 10^(-3) J`
C. `3.47 xx 10^(6) J`
D. `3.47 xx 10^(-6) J`

Answer

A

Explanation

Average themal energy of one mole of Helium
`=3/2 RT = 3/2 xx 8.31 xx 300 = 3.74 xx 10^(3)J`.