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If C(1), C(2), C(3)......are random spee...

If `C_(1), C_(2), C_(3)`......are random speed of gas molecules, then average speed `C_(av)= (C_(1)+C_(2)+C_(3)+...C_(n))/(n)` and root mean square speed of gas molecules, `C_(rms) = sqrt((C_(1)^(2)+C_(2)^(2)+C_(3)^(2)+...C_(n)^(2))/(n)) =C`. Further , `C_(2) prop T or C prop sqrt(T)` at `0k, C=0`, ie., molecular motion stops. With the help of the passage given above , choose the most appropriate alternative for each of the following question:
`KE` per molecule of the gas in the above question becomes x times, where x is

A

`1/2`

B

`1/4`

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
D
As, KE per molecule `prop T`
and T is doubled, therefore, kinetic energy per molecule becomes 2 times.
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