The total energy of a partical executing simple harmonic motion of period `2pi` secon is 10,240ert. The displacement of the particle at `pi//4` second is `8sqrt(2)cm`. Calculate the amplitutde of motion and mass of the particle

Explanation

To solve the problem step by step, we will find the amplitude of the motion and the mass of the particle executing simple harmonic motion (SHM) based on the given data.

### Step 1: Identify the given data
- Total energy (E) = 10,240 erg
- Time period (T) = \(2\pi\) seconds
- Displacement at \(t = \frac{\pi}{4}\) seconds, \(y\) = \(8\sqrt{2}\) cm

### Step 2: Calculate angular frequency (\(\omega\))
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