What is the ratio betweenthe potential energy and the total energy of a particel executing SHM, when its diplacement is half of its amplitude?

Explanation

`(Potential e n ergy)/(t o tal en e rgy)=((1)/(2)momega^(2)y^(2))/((1)/(2)momega^(2)A^(2))`
`(y^(2))/(A^(2))=(A//2)^(2)/(A^(2))=(1)/(4)`