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A 100 cm long wire of mass 40 g supports...

A 100 cm long wire of mass 40 g supports a mass of 1.6 kg as shown in figure . Find the fundamental frequency of the portion of the string between the wall and the pulley. Take `g=10m//s^(2)`.

Text Solution

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Here, mass`//`length `m=(20xx10^(-3))/(50//100)=0.04kg//m`
`T=1.6kg=1.6xx10N=16N.`
Length that vibrates, `L=50-10=40cm=0.4m. `
`v=(1)/(2L)sqrt((T)/(m))=(1)/(2xx0.4)sqrt((16)/(0.04))=(20)/(0.8)`
`=25Hz`
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