Calculate the ration of speed of sound in neon to that in water vapours at any temperature. Molecular weight on neon `=2.02xx10^(-2)kg//mol e` and for water vapours, molecular weight is `1.8xx10^(-2)kg//mol e`.

Explanation

Here, `M_(n)=2.02xx10^(-2)kg//mol e`
`M_(w)=1.8xx10^(-2)kg//m ol e`
As neon is monoatomic, therefore
`gamma_(n)=5//3`
and water vapours are non-linear triatomic.
`:. Gamma_(w)=4//3`
As `upsilon=sqrt((gammarho)/(rho))=sqrt((gamma RT)/(M))`
and T is same, therefore,
`(upsilon_(n))/(upsilon_(w))=sqrt((gamma_(n))/(M_(n))xxM_(w)/(gamma_(w)))=(5//3xx1.8xx10^(-2))/(2.02xx10^(-2)xx4//3)`
`=sqrt((5xx18)/(2.02xx4))=sqrt((9)/(8.08))=sqrt(1.1138)`
`(upsilon_(n))/(upsilon_(w))=1.055`