A diverging lens of focal length `15 cm` forms an image `10 cm` from the lens. Calculate the distance of the object from the lens, given `mu = 1.5`. What is the linear magnification of the image ?

Explanation

Here, `f = -15 cm, v = - 10 cm, u = ?, mu = 1.5`
As `(1)/(v)-(1)/(u) = (1)/(f) :. (1)/(u)=(1)/(v)-(1)/(f)=(1)/(-10)+(1)/(15)=(-3+2)/(30)=(-1)/(30) :. u = -30 cm`
Now `m = (v)/(u)=(-10)/(-30) = (1)/(3)`.