A light of wavelength `6000 A` in air, enters a medium with refractive index 1.5 Inside the medium its frequency is….Hz and its wavelength is ….`A`

Explanation

Here, `lamda = 6000 Å = 6 xx 10^-7 m`,
`mu = 1.5, lamda' = ?, v' = ?`
`lamda' = (lamda)/(mu) = (6000)/(1.5) = 4000 Å`
`v' = v = ( c)/(lamda) = (3 xx 10^8)/(6 xx 10^-7) = 5 xx 10^14 Hz`.