A ray of light is incident at an angle of `45^@` on one face of a rectangular glass slab of thickness `10 cm` and refractive index `1.5`. Calculate the lateral shift produced.

Explanation

Here, `i_1 = 45^@, t = 10 cm = 0.1 m`
`mu = 1.5`, lateral shift = ?
As `mu = (sin i_1)/(sin r_1)`
`:. sin r_1 = (sin i_1)/(mu) = (sin 45^@)/(1.5) = (0.707)/(1.5) = 0.4713`
`r_1 = sin^-1 (0.4713) = 28.14^@`
leteral shift `= (t sin(i_1 - r_1))/(cos r_1)`
=`(0.1 sin (45^@ - 28.14^@))/(cos 28.14^@)`
=`(0.1 sin 16.86^@)/(cos 28.14^@) = (0.1 xx 0.2900)/(0.8818) = 0.033 m`.