The refractive index of water is `4//3`. Determine the angle of the cone within which the entire outside view will be confined for a fish under water.

Explanation

A is clear from , the fish can see the entire outside view within cone angle
`theta = 2 C`, where sin `C = (1)/(mu) = (1)/(4//3) = 0.75`
`C = sin^(-1)(0.75) = 48.7^(@)`
`:. theta = 2 C = 2 xx 48.7 = 97.4^(@)`.
.