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The focal length of an equiconvex lens i...

The focal length of an equiconvex lens is equal to radius of curvature of either surface. What is the refractive index of the material of the prism ?

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To find the refractive index of the material of an equiconvex lens where the focal length (f) is equal to the radius of curvature (R) of either surface, we can use the lens maker's formula. The lens maker's formula is given by: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Where: - \( f \) is the focal length of the lens, ...
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Knowledge Check

  • The focal length of a double convex lens is equal to radius of curvature of either surface. The refractive index of its material is

    A
    `3//2`
    B
    `1`
    C
    `4//3`
    D
    none of these
  • The focal length of a plano-convex lens is equal to its radius of curvature. The value of the refractive index of its material is

    A
    1.33
    B
    1.6
    C
    1.5
    D
    2
  • The power of a biconvex lens is 10 D and the radius of curvature of each surface is 10 cm . Then the refractive index of the material of the lens is :

    A
    `3//2`
    B
    `4//3`
    C
    `9//8`
    D
    `5//3`
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