Home
Class 11
PHYSICS
The focal length of an equiconvex lens p...

The focal length of an equiconvex lens placed in air is equal to radius of curvature of either surface. Is it true ?

Text Solution

Verified by Experts

yes, `f = R` only when `mu = 1.5`. This follows from
`(1)/(f)=(mu - 1)((1)/(R_1) - (1)/(R_2)). If mu ne 1.5`, then `f ne R`.
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS

    PRADEEP|Exercise Short Answer(c)|18 Videos
  • RAY OPTICS

    PRADEEP|Exercise Short Answer(d)|17 Videos
  • RAY OPTICS

    PRADEEP|Exercise (NCERT)Very Short Answer|5 Videos
  • PROPERTIES OF BULK MATTER

    PRADEEP|Exercise Multiple choice questions|7 Videos
  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    PRADEEP|Exercise Assertion- Reason Type questions|20 Videos

Similar Questions

Explore conceptually related problems

Assertion : The focal length of an equiconvex lens placed in air to radius of curvature of either face. Reason : For an equiconvex lens radius of curvature of both the faces is same.

The focal length of an equiconvex lens is equal to radius of curvature of either surface. What is the refractive index of the material of the prism ?

The focal length of a double convex lens is equal to radius of curvature of either surface. The refractive index of its material is

Statement-1 : Focal length of an equiconvex lens of mu = 3//2 is equal to radius of curvature of each surface. Statement-2 : it follows from (1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))

The focal length of an equiconcave lens is 3/4 times of radius of curvature of its surfaces. find the refractive index of the material of lens. under what condition will this lens behave as a converging lens?

The focal length of equiconvex lens of retractive index, mu=1.5 and radius of curvature, R is

The focal length of a plano-convex lens is equal to its radius of curvature. The value of the refractive index of its material is

What is the focal length of double convex lens for which radius of curvature of either of the surfaces is 30 cm? [ ""_(a) mu_(g)=1.5]

The focal length of a convex lens is 10 cm and its refractive index is 1.5. If the radius of curvature of one surface is 7.5 cm , the radius of curvature of the second surface will be

The focal length of a convex lens is 10 cm and its refractive index is 1.5 . If the radius of curvature of one surface is 7.5 cm, the radius of curvature of the second surface will be :

PRADEEP-RAY OPTICS-Short Answer(b)
  1. Why does the rising sun appear oval shaped ?

    Text Solution

    |

  2. Where should an object be placed from a convex lens to from an image o...

    Text Solution

    |

  3. The focal length of an equiconvex lens placed in air is equal to radiu...

    Text Solution

    |

  4. Within a glass slab, a double convex air bubble is formed. How would t...

    Text Solution

    |

  5. Why does a convex lens of glass mu = 1.5 behave as a diverging lens wh...

    Text Solution

    |

  6. A diverging lens of focal length F is cut into two idential parts, eac...

    Text Solution

    |

  7. Draw a plot showing the variation of power of a lens with the wavelen...

    Text Solution

    |

  8. A lens whose radii of curvature are different is forming the image of ...

    Text Solution

    |

  9. The image of a candle is formed by a convex lens on a screen. If the l...

    Text Solution

    |

  10. A convex lens forms the image of the sun at a distance of 10 cm. Where...

    Text Solution

    |

  11. An equiconvex lens of focal length 15 cm is cut into two equal halves ...

    Text Solution

    |

  12. A lens shown in Fig. 6(b).75 is made of two different materials. A poi...

    Text Solution

    |

  13. What is focal length and power of a rectangular glass slab ?

    Text Solution

    |

  14. How does focal length of a convex lens change if violet light is used ...

    Text Solution

    |

  15. Two thin lenses of power + 3 D and - 1 D are held contact with each ot...

    Text Solution

    |

  16. In Fig., line AB represents a lens through which course of rays is as ...

    Text Solution

    |

  17. Explain with reason how the power of a diverging lens changes when (...

    Text Solution

    |

  18. A ray of light suffers lateral displacement on passing through a paral...

    Text Solution

    |

  19. Prove that mu = (1)/(sin C)' where C is the critical angle.

    Text Solution

    |

  20. What are optical fibers ? Give three appilications of these fibres.

    Text Solution

    |