Prove that `mu = (1)/(sin C)`' where `C` is the critical angle.

The velocity of light through media 'A' and 'B' are V and 2V, respectively. The value of sin C is ______ [where 'C' is the critical angle].

A ray of light passes from glass (mu_(g) = 1.52) to water (mu_(w) = 1.33) . What is the critical angle of incidence?

Critical angle of glass is theta_(1) and that of water is theta_(2) . The critical angle for water and glass surface would be (mu_(g) = 3//2,mu_(w) = 4//3)

Critical angle of glass is theta_(1) and that of water is theta_(2) . The critical angle for water and glass surface would be (mu_(g)=3//2, mu_(w)=4//3)

An optical fibre (mu = 1.72) is surrounded by a glass coating (mu= 1.50). Find the critical angle for total internal reflection at the fibre-glass interface.

A right - angled isoceles prism is held on the surface of a liquid composed of miscible solvents A and B of refractive index n_A = 1.50 and n_B = 1.30 respectively . The refractive index of prism is n_p = 1.5 and that of the liquid is given by N_L = C_A n_A +(1 -C_A) n_B where C_A is the percentage of solventA in the liquid IF theta_C is the critical angle at prism - liquid interface . the plot which best represents the variation of the critical angle with the percentage of solvent is

Find the angle of refraction in a medium (mu=2) if light is incident in vacuum, making an angle equal to twice the critical angle.

A, B and C are three optical media of respective critical angles C_1 , C_2 and C_3 . Total internal reflection of light can occur from A and B and also from B to C but not from C to A. Then the correct relation between critical angles is

In Delta ABC, prove that tan A+tan B+tan C>=3sqrt(3), where A,B,C are acute angles.