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What happens when sixe of scatterer is m...

What happens when sixe of scatterer is much bigger than the wavelength of light ?

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When size of scatterer is much bigger than wavelength of light. Rayleigh scattering is not valid. In that case, all wavelength/colours are scattered equally.
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(a) What is the essential condition for Rayleigh scattering ? (b) In Rayleigh scattering, how is intensity of scattered light related to wavelength of light ?

Knowledge Check

  • When size of scatterer (x) is very much less than the wavelength (lamda) of light, intensity of scattered light (I_s) varies as :

    A
    `I_s prop (1)/(lamda)`
    B
    `I_s prop (1)/(lamda^2)`
    C
    `I_s prop (1)/(lambda^4)`
    D
    `I_s prop (1)/(lamda^6)`

  • (a) True solutions do not exhibit tyndall effect. (r) in true solutions, size of solute particles is much smaller than the wavelength of light used.

    A
    IF both (A) and (r) are correct and (r) is the correct explanation for (a).
    B
    If both (a) and (r) are correct but (r) is not the correct explanation for (a).
    C
    IF (a) is correct but (r) is incorrect.
    D
    If (a) is incorrect but (r) is correct.

  • Tyndal effect is observed when- (A) Diameter of dispersed particles is not much smaller than the wavelength of light used (B) The refractive indices of the dispersed phase and the dispersion medium differ greatly in magnitude ( C) Diameter of dispersed particles is much larger than the wavelength of the light used

    A
    a and b
    B
    a and c
    C
    b and c
    D
    a,b and c

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    How does amount of scattering depend on the wavelength of light used ?

    Assertion (A): Scattering of light is the reflection of light from an object in all directions. Reason (R): The colour of scattered light depends on the size of scattering particles and wavelength of light.

    If a is the size of scatterer and lamda is the wavelength of light then Rayleigh law of scattering is valid for

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