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Light of wavelength 5000Å falls on a pla...

Light of wavelength `5000Å` falls on a plane reflecting surface. What are the wavelength and frequency of reflected light ? For what angle of incidence is the reflected ray normal to the incident ray ?

Text Solution

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Here, `lamda = 5000 Å = 5 xx 10^-7 m`
`v = ( c)/(lamda) = (3 xx 10^8)/(5 xx 10^-7) = 6 xx 10^14 hertz`
On reflection, there is no change in wavelength or frequency. Therefore,
`lamda' = lamda = 5000 Å , v' = v = 6 xx 10^14 Hz`
for reflected ray to be normal to incident ray,
`i+ r = 90^@` or `i+ i= 90^@` `(because r = i)`
`:. i= 90//2 = 45^@`.
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Light of wavelength 5000 Å falls on a plane reflecting surface. What are the wavelength and frequency of the reflected light ? For what angle of incidence is the reflected ray normal to the incident ray ?

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Knowledge Check

  • Light of wavelength 6000Å falls on a plane reflecting surface. The reflected wavelength is

    A
    `6000Å`
    B
    `lt 6000Å`
    C
    `gt 6000Å`
    D
    cannot say
  • Light of wavelength 6000 Å falls on a plane reflecting surface. The reflected wavelength is.

    A
    `6000 Å`
    B
    `lt 6000 Å`
    C
    `gt 6000 Å`
    D
    cannot say
  • Ligtht falls on a plane reflecting surface.For what angler of incidence is the reflected ray normal to the incident ray.

    A
    `60^(@)`
    B
    `45^(@)`
    C
    `90^(@)`
    D
    `30^(@)`
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