Home
Class 11
PHYSICS
In normal adjusment of telescope, final ...

In normal adjusment of telescope, final image is……. . And distance between objective lens and eye lens is………. .

Text Solution

Verified by Experts

at infinity , `(f_0 + f_e)`.
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS

    PRADEEP|Exercise (Exemplar) Multiple choice|16 Videos
  • RAY OPTICS

    PRADEEP|Exercise (Competition)Multiple choice|89 Videos
  • RAY OPTICS

    PRADEEP|Exercise (Test Your Grip)Fill in the blanks (c)|10 Videos
  • PROPERTIES OF BULK MATTER

    PRADEEP|Exercise Multiple choice questions|7 Videos
  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    PRADEEP|Exercise Assertion- Reason Type questions|20 Videos

Similar Questions

Explore conceptually related problems

In a compound microscope, the distance between objective lens and eye lens is.

The magnifying power of an astronomical telescope for relaxed vision is 16. On adjusting, the distance between the objective and eye lens is 34 cm . Then the focal length of objective and eye lens will be respectively

A telescope has been adjusted for relaxed eye. How will you change the distance between objective lens and eye if final image is to be seen at the least distance of distinct vision ?

In an astronomical telescope, the distance between the objective lens and eyepiece is 20 cm. In normal adjustment, the magnifying power of the telescope is 15. Find the focal length of the objectives lens.

A compound microscope is made using a lens of focal 10 mm as objective and another lens of focal length 15 mm as eye piece. An object is held 1.1 cm from the objective and final image is obtained at oo . Calculate distance between objective and eye piece.

Is angular magnification of a telescope equal to ratio of diameters of objective and eye lens ?

The focal lengths of the objective and eyelens of a microscope are 1.6 cm and 2.5 cm respectively. The distance between the two lenses is 21.7 cm. If the final image is formed at infinity, the distance between the object and the objective lens is :

A convex lens forms an image of an object on a screen ,The height of the image is 9cm The lens is now disiplaced between the object on the screen.the height of this image is 4cm .the distance between the object and the screen is 90cm

An astronomical telescope has a magnifying power of 10 . In normal adjustment, distance between the objective and eye piece is 22 cm calculate focal length of objective lens.