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For the angle of minimum deviation of a...

For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index

A

lies between `sqrt(2)` and `1`

B

lies between `2` and `sqrt(2)`

C

is less than `1`

D

is greater than `2`

Text Solution

Verified by Experts

The correct Answer is:
B

From prism formula, `mu = (sin(A + delta_m)//2)/(sin A//2)`
For `delta_m = A`,
`mu = (sin A)/(sin A//2)`
=`(2 sin A//2 cos A//2)/(sin A//2) = 2 cos A//2`
When `A = 0^@, mu_(max) = 2 cos 0^@ = 2`
When `A = 90^@, mu_(min) = 2 cos 45^@ = (2)/(sqrt(2)) = sqrt(2)`
Choice (b) is correct.
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