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Statement-1 : When a prism of mu = 3//2 ...

Statement-1 : When a prism of `mu = 3//2` is immersed in water `(mu = 4//3)`, deviation through the prism becomes `1//4th` of the deviation, when the prism is in air.
Statement-2 : It follows from `delta = (mu - 1)A`

A

Statement - 1 true, Statement - 2 is true. Statement - 2 is correct explanation of statement - 1.

B

Statement - 1 is true, Statement - 2 is true, but Statement - 2 is not a correct explanation of Statement - 1.

C

Statement - 1 is true, Statement - 2 is false.

D

Statement - 1 is false, Statement - 2 is true.

Text Solution

Verified by Experts

The correct Answer is:
A

When prism is in air,
`delta_a = (mu -1) A = (3//2 - 1) A = A//2`
When prism is in water,
`delta_m = ((mu_g)/(mu_w) - ) A = ((3//2)/(4//3) - 1) A = (A)/(8) = (delta_a)/(4)`
Both the statement are true and statement-2 is correct explanation of statement-1.
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