Calculate the speed of light in a medium whose critical angle is `45^(@)`.

Answer

`2.12 xx 10^(8) m//s`

Explanation

Here, `v = ?, C = 45^(@)`
`mu = (1)/(sin C) = (1)/(45^(@)) = sqrt(2)`
`v = ( c)/(mu) = (3 xx 10^(8)m//s)/(sqrt(2)) = 2.12 xx 10^(8)m//s`