Find the radius of curvature of convex surface of a plano convex lens, whose focal length is `0.3 m and mu = 1.5`.

Answer

`0.15 m`

Explanation

Here, `R_(2) = ? f = 0.3 m, mu = 1.5`
For plane surface of lens, `R_(1) = oo : R_(2) = - R`
From lens formula : `(1)/(f) = (mu -1)((1)/(R_(1)) - (1)/(R_(2)))`
`(1)/(0.3) = (1.5 - 1)((1)/(oo) + (1)/(R )) = (1)/(2 R)`
`R = 0.15 m`