Calculate the refractive index of the material of an equilaterial prism for which angle of minimum deviation is `60^@`.

Answer

`sqrt(3)`

Explanation

Here, `A = 60^(@), delta_(m) = 60^(@), mu = ?`
`mu = (sin (A + delta_(m))//2)/(sin A//2) = (sin (60^(@) + 60^(@))//2)/(sin 60^(@)//2)`
`= (sin 60^(@))/(sin 30^(@)) = (sqrt(3)//2)/(1//2) = sqrt(3)`