A ray of light is inclined to one face of a prism at an angle of `60^@`. If angle of prism is `60^@` and the ray deviated through an angle of `42^@` find the angle which the emergent ray makes with second face of the prism.

Answer

`28^(@)`

Explanation

Here, `I = 90^(@) - 50^(@) = 40^(@), A = 60^(@), delta = 42^(@), i_(2) = ?`
As `i_(1) + i_(2) = A + delta`
`i_(2) = A + delta - i_(1) = 60^(@) + 42^(@) - 40^(@) = 62^(@)`
Angle which the emergent ray makes with the second face of the prism `= 90^(@) - 62^(@) = 28^(@)`