In Young's double-slit experiment the angular width of a fringe formed on a distant screen is `1^(@)`. The wavelength of light used is `6000 Å`. What is the spacing between the slits?

Answer

`3.44 xx 10^(-4)m`

Explanation

`theta = 0.1^(@) = 0.1 xx (pi)/(180) radian`
`lambda = 6000 Å = 6 xx 10^(-7)m, d = ?`
As angular width, `theta = (lambda)/(d)`
`:. d = (lambda)/(theta) = (6 xx 10^(-7))/(0.1 xx pi//180) = (180 xx 6 xx10^(-7))/(0.1 xx 3.14)`
`= 3.44 xx 10^(-4)m`