In YDSE, light of wavelength `5000 Å` is used. The third bright band on the screen is formed at a distance of `1 cm` from the central bright band. If the screen is at a distance of `1.5 m` from the centre of narrow slits, calculate the separation between the slits.

Answer

`2.25 xx 10^(-4) m`

Explanation

Here,`lambda = 5000 Å = 5 xx 10^(-7)m, n =3`
`x_(3) = 1 cm = 10^(-2)m, D = 1.5m, d = ?`
`x_(3) = n (lambda D)/(d)`
`10^(-2) = 3 xx 510^(-7) xx (1.5)/(d) = (22.5 xx 10^(2))/(d)`
`d = (22.5 xx 10^(-7))/(10^(-2)) = 22.5 xx 10^(-5)m`
`= 2.25 xx 10^(-4)m`