Determine the angular spread between central maximum and first order maximum of the diffraction pattern due to a single slit of width `0.25 mm`, when light of wavelength `5890 Å` is incident on it normally ?

Answer

`3.53 xx 10^(-3) rad`

Explanation

Here, `a = 0.25 mm = 0.25 xx 10^(-3)m`
`lambda = 5890 Å = 5890 xx 10^(-10)m`
Angular separation between central maximum and first maximum
`theta_(1)' = (3 lambda)/(2a) = (3 xx 5890 xx 10^(-10))/(2 xx 0.25 xx 10^(-3))`
`= 3.53 xx 10^(-3) radian`