Calculate the numarical aperture of a microscope required to just resolve two points separated by a distance of `10^(-4) cm`. Wavelength of light used is `5.8 xx 10^(-5) cm`.

Answer

`0.29`

Explanation

N.A `= mu = sin theta = ?`
`d = 10^(-4)cm, lambda = 5.8 xx 10^(-5) cm`
N.A `= mu sin theta = (lambda)/(2 d) = (5.8 xx 10^(-5))/(2 xx 10^(-4)) = 0.29`