Light incident on a surface separating two media is partly reflected and party refracted as shown in Fig. Then :
.

Options

A. `sin i = (mu_(2))/((mu_(1)^(2) + mu_(2)^(2))^(1//2))`
B. `tan i = (mu_(1))/(mu_(2))`
C. `sin i = mu_(1) mu_(2)`
D. `sin i = (mu_(2))/(mu_(1))`

Answer

A

Explanation

As the reflected and refracted components are perpendicular to each other, therefore, `i` must be the polarizing angle. According to Brewster's law,
`mu = tan i`
As `(sin i)/(sin r) = (mu_(2))/(mu_(1)) = mu = tan i`

`:.` From Fig.
`sin i = (mu_(2))/((mu_(2)^(2) + mu_(1)^(2))^(1//2))`