A planet is observed by an astronomical refracting telescope having an objective of ofcal length 16m and an eyepiece of focal length 2 cm. Then,

Options

A. The distance between the objective and eye piece is `16.02 m`
B. The angular magnification of the planet is `- 800`
C. The image of the planet is inverted
D. The objective is larger than his eye piece

Answer

A, B, C, D

Explanation

(a) distance between objective and eye piece
`L = f_(0) + f_(e) = 16 + 0.02 = 16.02 m`
(b) magnification of telescope
`M = (f_(0))/(f_(e)) = (16)/(-0.02) = - 800`
(c ) final image formed by astronomical telescope is always inverted
(d) The aperture of objective in astronomical be coherent is larger than that of eye piece