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Statement-1 : Focal length of an equicon...

Statement-1 : Focal length of an equiconvex lens of `mu = 3//2` is equal to radius of curvature of each surface.
Statement-2 : it follows from
`(1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))`

A

Statement-1 is true, Statement-2 is true.
Statement-2 is correct explanation of Statement-1.

B

Statement-1 is true, Statement-2 is true, but Statement-2 is not a correct explanation of Statement-1.

C

Statement-1 is true, Statement-2 is false.

D

Statement-1 is fasle, Statement-2 is true.

Text Solution

Verified by Experts

The correct Answer is:
A
For an equiconvex lens, if `R_(1) = R, R_(2) = - R`
`:. (1)/(f) = ((3)/(2) - 1)((1)/(R ) + (1)/(R )) = (1)/(R )`
`f = R`
Hence both the statement are true and statement-2 is correct explanation of statement-1.
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Knowledge Check

  • The focal length of equiconvex lens of retractive index, mu=1.5 and radius of curvature, R is

    A
    `R / 1.5`
    B
    `1.5/R`
    C
    R
    D
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    A
    STATEMENT -`1`is true statement `2` is true,Statement -`2`is a correct explanation for statement -`1`
    B
    STATEMENT -`1`is true statement `2` is true,Statement -`2`is a not a correct explanation for statement -`1`
    C
    Statement -`1`is true,Statement -`2`is False
    D
    Statement -`1`is False ,Statement -`2`is True

  • What is the focal length of double convex lens for which radius of curvature of either of the surfaces is 30 cm? [ ""_(a) mu_(g)=1.5]

    A
    50 cm
    B
    30 cm
    C
    `-30 cm`
    D
    `-50 cm`

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