Using the graph shown in fig for stopping potential `v_s` the incident frequency of photons, calculate Planck's constant.

Explanation

Here, `DeltaV_0=1.23-0=1.23V`,
From Eienstein's Photoelectric equation
`eV_0=hv-phi_0`
On differentiating it, we get
`eDeltaV_0=hDeltav`
or `h=(eDeltaV_0)/(Deltav)=((1.6xx10^(-19))xx1.23)/((8-5)xx10^(14))`
`=6.56xx10^(-34)Js`