Find the de-Broglie wavelength of an electron in a metal at `127^@C`. Given, mass of electron `=9.11xx10^(-31)kg`, Boltsmann constant `=1.38xx10^(-23)"J mole"^-1K^-1` , Plank constant `=6.63xx10^(-34)Js`.

Explanation

Here, `T=127+273=400K , m=9.11xx10^(-31)kg`.
De-Broglie wavelength of electron is
`lambda=h/(sqrt(3mkT))=(6.63xx10^(-34))/(sqrt(3xx(9.11xx10^(-31))xx(1.38xx10^(-23))xx400))=(6.63xx10^(-34))/(12.28xx10^(-26))=5.3xx10^-9m`