The work function `(phi_0)`, of a metal X, equals `3xx10^(-19)J`. Calculate the number (N) of photons, of light of wavelength 26.52nm, whose total energy equal W. Plank's constant `=6.63xx10^(-34)Js.`

Explanation

To solve the problem, we need to calculate the number of photons (N) required such that their total energy equals the work function (φ₀) of the metal X. Here are the steps to find the solution:

### Step 1: Identify the given values
- Work function (φ₀) = \(3 \times 10^{-19} \, \text{J}\)
- Wavelength (λ) = \(26.52 \, \text{nm} = 26.52 \times 10^{-9} \, \text{m}\)
- Planck's constant (h) = \(6.63 \times 10^{-34} \, \text{Js}\)

### Step 2: Calculate the energy of one photon
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