Photoelectrons are emitted from a metal surface when ultraviolet light of wavelength 300nm is incident on it. The minimum negative potential required on it. The minimum negative potential required to stop the emission of electrons is 0.54V. Calculate:
(i) the energy of the incident photons
(ii) the maximum kinetic energy of the photoelectrons emitted
(iii) the work function of the metal Express all answer in eV. `(use h=6.63xx10^(-34)Js)`

Explanation

To solve the problem step by step, we will calculate the energy of the incident photons, the maximum kinetic energy of the emitted photoelectrons, and the work function of the metal.

### Given Data:
- Wavelength of incident light, \( \lambda = 300 \, \text{nm} = 300 \times 10^{-9} \, \text{m} \)
- Stopping potential, \( V_0 = 0.54 \, \text{V} \)
- Planck's constant, \( h = 6.63 \times 10^{-34} \, \text{Js} \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)
- Charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)
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