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A source of light is placed at a distanc...

A source of light is placed at a distance of 1m. From a photocell and the cut off potential is found to be `V_0.` If the distance is doubled what will be the cut off potential?

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`V_0`. When distance is double, the intensity of incident light becomes one-fourth `(Iprop1//r^2)`, but the frequency of incident light remains unchanged. The value of cut off potential of a material only depends upon the frequency of the incident light and is independent of the intensity of incident light.
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PRADEEP-DUAL NATURE OF RADIATION AND MATTER-Exercise
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