Is the de-Broglie wavelength of a photon of an electromagnetic radiation equal to the wavelength of the radiation?

Explanation

Yes, de-Broglie wavelength for a photon is given by
`lambda=h/(mv)=h/p...(i)`
Where p is the momentum of photon and h is the Plank's constant.
The momentum of a photon of frequency v is given by
`p=(hv)/c =h/lambda or lambda=h/p....(ii)`
It is the same wavelength as de-Broglie wavelength of the photon.