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Ultraviolet light is incident on two photosenstive materials having work functions `phi_1` and `phi_2 (phi_1 gt phi_2)`. In which case will the K.E. of the emitted electrons be greater ? Why ?

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Max. K.E. of photoelectron, `K_(max)=hv-phi_0`, As `phi_1 gt phi_2`, so the max. K.E. of the emitted photoelectrons will be greater for the photosenstive material having work function `phi_2`.
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PRADEEP-DUAL NATURE OF RADIATION AND MATTER-Exercise
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  2. The photoelectric effect can be explained on the basis of

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  3. Which of the following has minimum stopping potential?

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  6. The maximum velocity of an electron emitted by light of wavelength lam...

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  7. The photoelectric work function for a metal surface is 4.125 eV. The c...

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  10. The work function for metals A , B and C are respectively 1.92 eV , 2....

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  14. The minimum energy required by an electron to..........form the metal ...

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  15. The maximum kinetic energy of emitted photoelectrons depends on the......

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  16. The ratio of number of photoelectrons ejected to the number of the pho...

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  17. For given photosenstive material, the photoelectric current is...........

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  18. An increase in the frequency of the incident light.............the vel...

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  19. The minimum energy required to ejected an electron from the surface of...

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  20. In photoelectric effect the energy of the free electron does not depen...

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