A photon and an elecron have the same de Broglie wavelength. Which has greater total energy? Explain

Explanation

For a photon, energy,
`E_1=hv=hc//lambda.....(i)`
For an electron moving with velocity v, and effective mass m, de-Broglie wavelength `(lambda)` is given by
`lambda=h/(mv) or m=h/(lambda v) .....(ii)`
Total energy of electron,
`E_2=mc^2=h/(lambda v) c^2` from (ii)
`:. (E_2)/(E_1)=(hc^2//lambdav)/(hc//lambda)=c/vgt1`
Hence, `E_2gtE_1` It shows that total energy of an electron is greater than of photon