Light of frequency `7.21xx10^(14)Hz` is incident on a metal surface. Electrons with a maximum speed of `6.0xx10^(5)ms^(-1)` are ejected from the surface. What is the threshold frequency for photoemission of electrons? `h=6.63xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg`.

Explanation

To find the threshold frequency for photoemission of electrons, we will use Einstein's photoelectric equation. The equation relates the maximum kinetic energy of the ejected electrons to the frequency of the incident light and the threshold frequency.

### Step-by-Step Solution:

1. **Identify the given values**:
- Frequency of incident light, \( \nu = 7.21 \times 10^{14} \, \text{Hz} \)
- Maximum speed of ejected electrons, \( v_{\text{max}} = 6.0 \times 10^{5} \, \text{m/s} \)
- Planck's constant, \( h = 6.63 \times 10^{-34} \, \text{Js} \)
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