An electron and a photon each has a wavelength of 1.0nm. Find (a) their momenta, (b) the energy of the photon , and © the kinetic energy electron.
Take `h=6.63xx10^(-34) Js`.

Explanation

(a) For electron or photon, momentum, `p=h/lambda=(6.63xx10^(-34))/(10^(-9))=6.63xx10^(-25)m`
(b) `E=(hc)/lambda=((6.63xx10^(-34))xx(3xx10^(8)))/(10^(-9)xx(1.6xx10^(-19)))=1243eV , (c) K=1/2 (p^(2))/m =1/2xx((6.63xx10^(-25))^(2))/(9xx10^(-31)xx(1.6xx10^(-19)))=1.52eV`