Compute the typical de-Broglie wavelength of an electrons in a metal at `27^(@)C` and compare it with the mean separation between two electrons in a metal which is given to be about `2xx10^(-10)m`.

Explanation

For an electron in metal, momentum is `p=sqrt(3mkT)=sqrt(3xx(9.11xx10^(-31))xx(1.38xx10^(-23))xx300)`
`1.06xx10^(-25)kgms^(-1)`
De-Broglie wavelength `lambda=h/p=(6.63xx10^(-34))/(1.06xx10^(-25)) =62.6xx10^(-10)m`
Mean separation between two electrons in a metal, `r=2xx10^(-10)m :. lambda/r= (62.6xx10^(-10))/(2xx10^(-10))=31.3`